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15w^2-25w=0
a = 15; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·15·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*15}=\frac{0}{30} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*15}=\frac{50}{30} =1+2/3 $
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